notes/OJ notes/pages/Leetcode Linked-List-Cycle.md
2022-09-07 21:30:22 +08:00

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# Leetcode Linked-List-Cycle
#### 2022-06-14 21:54
---
##### Algorithms:
#algorithm #Floyd_s_cycle_finding_algorithm
##### Data structures:
#DS #linked_list
##### Difficulty:
#leetcode #coding_problem #difficulty_easy
##### Related topics:
##### Links:
- [Link to problem](https://leetcode.com/problems/linked-list-cycle/)
---
### Problem
Given `head`, the head of a linked list, determine if the linked list has a cycle in it.
There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the `next` pointer. Internally, `pos` is used to denote the index of the node that tail's `next` pointer is connected to. **Note that `pos` is not passed as a parameter**.
Return `true` _if there is a cycle in the linked list_. Otherwise, return `false`.
**Follow up:** Can you solve it using `O(1)` (i.e. constant) memory?
#### Examples
**Example 1:**
![example1](https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist.png)
```markdown
**Input:** head = [3,2,0,-4], pos = 1
**Output:** true
**Explanation:** There is a cycle in the linked list, where the tail connects to the 1st node (0-indexed).
```
**Example 2:**
![example2](https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist_test2.png)
```markdown
**Input:** head = [1,2], pos = 0
**Output:** true
**Explanation:** There is a cycle in the linked list, where the tail connects to the 0th node.
```
**Example 3:**
![example3](https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist_test3.png)
```markdown
**Input:** head = [1], pos = -1
**Output:** false
**Explanation:** There is no cycle in the linked list.
```
#### Constraints
- The number of the nodes in the list is in the range `[0, 104]`.
- `-105 <= Node.val <= 105`
- `pos` is `-1` or a **valid index** in the linked-list.
### Thoughts
> [!summary] > **Algorithm:**
> This is a #Floyd_s_cycle_finding_algorithm.
> This is pretty straightforward, visit [[Floyd's Cycle Finding Algorithm]] for more info
### Solution
O(n)
```cpp
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
ListNode *slow = head;
ListNode *fast = head;
while (fast != NULL && fast->next != NULL) {
slow = slow->next;
fast = fast->next->next;
if (slow == fast) {
return true;
}
}
return false;
}
};
```