logseq_notes/pages/OJ notes/pages/Leetcode Design-Hash.md
2023-06-14 14:27:22 +08:00

2.6 KiB

Leetcode Design-Hash

2022-09-01 14:44

Data structures:

#DS #array #linked_list

Difficulty:

#coding_problems #difficulty_easy

Additional tags:

#leetcode #CS_list_need_practicing

Revisions:

N/A

Problem

Design a HashMap without using any built-in hash table libraries.

Implement the MyHashMap class:

  • MyHashMap() initializes the object with an empty map.

  • void put(int key, int value) inserts a (key, value) pair into the HashMap. If the key already exists in the map, update the corresponding value.

  • int get(int key) returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.

  • void remove(key) removes the key and its corresponding value if the map contains the mapping for the key.

  • Examples

    **Example 1:**
    
    **Input**
    ["MyHashMap", "put", "put", "get", "get", "put", "get", "remove", "get"]
    [[], [1, 1], [2, 2], [1], [3], [2, 1], [2], [2], [2]]
    **Output**
    [null, null, null, 1, -1, null, 1, null, -1]
    
    **Explanation**
    MyHashMap myHashMap = new MyHashMap();
    myHashMap.put(1, 1); // The map is now [[1,1]]
    myHashMap.put(2, 2); // The map is now [[1,1], [2,2]]
    myHashMap.get(1); // return 1, The map is now [[1,1], [2,2]]
    myHashMap.get(3); // return -1 (i.e., not found), The map is now [[1,1], [2,2]]
    myHashMap.put(2, 1); // The map is now [[1,1], [2,1]] (i.e., update the existing value)
    myHashMap.get(2); // return 1, The map is now [[1,1], [2,1]]
    myHashMap.remove(2); // remove the mapping for 2, The map is now [[1,1]]
    myHashMap.get(2); // return -1 (i.e., not found), The map is now [[1,1]]
    

Constraints

  • 0 <= key, value <= 106
  • At most 104 calls will be made to put, get, and remove.

Thoughts

[!summary] This is a #array problem.

Easy way:

Using array, since 10^6 size is not too large

Hard way:

Using hashes with linked list to support collision check.

Solution

Easy way:

class MyHashMap {
int myMap[1000001];

public:
MyHashMap() { fill(myMap, myMap + 1000001, -1); }

void put(int key, int value) { myMap[key] = value; }

int get(int key) { return myMap[key]; }

void remove(int key) { myMap[key] = -1; }
};

/**
 * Your MyHashMap object will be instantiated and called as such:
 * MyHashMap* obj = new MyHashMap();
 * obj->put(key,value);
 * int param_2 = obj->get(key);
 * obj->remove(key);
 */