logseq_notes/pages/OJ notes/pages/Leetcode Ransom-Note.md
2023-06-14 14:27:22 +08:00

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# Leetcode Ransom-Note
#### 2022-06-14 13:19
---
##### Algorithms:
#algorithm #hash_table
##### Data structures:
#DS #string #array
##### Difficulty:
#leetcode #coding_problems #difficulty_easy
##### Related topics:
##### Links:
- [Link to problem](https://leetcode.com/problems/ransom-note/)
***
### Problem
Given two strings `ransomNote` and `magazine`, return `true` _if_ `ransomNote` _can be constructed by using the letters from_ `magazine` _and_ `false` _otherwise_.
Each letter in `magazine` can only be used once in `ransomNote`.
#### Examples
**Example 1:**
```markdown
**Input:** s = "leetcode"
**Output:** 0
```
**Example 2:**
```markdown
**Input:** s = "loveleetcode"
**Output:** 2
```
**Example 3:**
```markdown
**Input:** s = "aabb"
**Output:** -1
```
#### Constraints
**Constraints:**
- `1 <= s.length <= 105`
- `s` consists of only lowercase English letters.
### Thoughts
Super simple hash map, similar to [[Leetcode First-Unique-Character-In-a-String]]
### Solution
O(m + n)
```cpp
class Solution {
public:
bool canConstruct(string ransomNote, string magazine) {
// hashmap, O(m + n)
int hashMap[26] = {};
for (char c : magazine) {
hashMap[c - 'a']++;
}
for (char c : ransomNote) {
if (hashMap[c - 'a']-- == 0)
return false;
}
return true;
}
};
```