# Leetcode Rotate-Array #### 2022-07-10 08:54 > ##### Algorithms: > #algorithm #array_in_place_operation #reverse_array > ##### Data structures: > #DS #array > ##### Difficulty: > #coding_problem #difficulty-medium > ##### Additional tags: > #leetcode #CS_list_need_practicing #CS_list_need_understanding > ##### Revisions: > N/A ##### Related topics: ```expander tag:#array_in_place_operation OR #reverse_array ``` ##### Links: - [Link to problem](https://leetcode.com/problems/rotate-array/) ___ ### Problem Given an array, rotate the array to the right by `k` steps, where `k` is non-negative. #### Examples **Example 1:** **Input:** nums = [1,2,3,4,5,6,7], k = 3 **Output:** [5,6,7,1,2,3,4] **Explanation:** rotate 1 steps to the right: [7,1,2,3,4,5,6] rotate 2 steps to the right: [6,7,1,2,3,4,5] rotate 3 steps to the right: [5,6,7,1,2,3,4] **Example 2:** **Input:** nums = [-1,-100,3,99], k = 2 **Output:** [3,99,-1,-100] **Explanation:** rotate 1 steps to the right: [99,-1,-100,3] rotate 2 steps to the right: [3,99,-1,-100] #### Constraints - `1 <= nums.length <= 105` - `-231 <= nums[i] <= 231 - 1` - `0 <= k <= 105` ### Thoughts #### Method 1: Array In-place operation This one is hard. ==#TODO: Revisit this one some other day== - Reversing a subarray doesn't change the continuity, the neighbors inside the subarray is same. - Reversing a subarray changes the edge's neighbors Suppose a array looks like: ``` [1, 2,| 3, 4, 5] ``` If reverse all two subarrays, the neighbors isn't changed only the orders are changed ``` [1, 2,| 3, 4, 5]: 5-1-2, 1-2-3, 2-3-4, 4-5-1 [2, 1,| 5, 4, 3]: 3-2-1, 2-1-5, 5-1-4, 4-3-2 ``` When reversed back, the order is changed back to original, but the two sub-arrays are swapped ``` [3, 4, 5,| 1, 2] ``` By doing this, the order in inner-array isn't changed, but the order of all is changed. #### Method 2: Copy Watch out for integer overflow. #### Method 3: CPP's STL sway subarrays Remember to sanitize k, when k > size ### Solution Method 1: ```cpp ``` Method 2: ```cpp class Solution { void swap(vector &nums, int l, int r) { int temp = nums[l]; nums[l] = nums[r]; nums[r] = temp; } public: void rotate(vector &nums, int k) { int size = nums.size(); if (size <= 1) { return; } // Copy k = size - k; while (k < 0) { k += size; } vector ans(nums.size()); for (int i = 0; i < size; i++) { ans[i] = nums[(i + k) % size]; } for (int i = 0; i < size; i++) { nums[i] = ans[i]; } } }; ``` Method 3: ```cpp class Solution { void swap(vector &nums, int l, int r) { int temp = nums[l]; nums[l] = nums[r]; nums[r] = temp; } public: void rotate(vector &nums, int k) { int size = nums.size(); if (size <= 1) { return; } // STL k = k % size; k = size - k; while (k < 0) { k += size; } nums.insert(nums.end(), nums.begin(), nums.begin() + k); nums.erase(nums.begin(), nums.begin() + k); } }; ```