vault backup: 2022-07-02 08:27:19

CS notes/pages/Leetcode Reverse-Linked-List.md

@@ -75,8 +75,7 @@ The in place insert is easier to understand, and simple to implement, using a ve
 ### Solution
 I've referred to this guy: https://leetcode.com/problems/reverse-linked-list/discuss/58130/C%2B%2B-Iterative-and-Recursive
 
-This code is hard to understand.
+Insertion, iteration
-==TODO==: Make my own version
 ```cpp
 class Solution {
 public:
@@ -99,27 +98,34 @@ public:
 ```
 
 Recursion:
-==TODO== Needs revision!
 ```cpp
+/**
+ * Definition for singly-linked list.
+ * struct ListNode {
+ *     int val;
+ *     ListNode *next;
+ *     ListNode() : val(0), next(nullptr) {}
+ *     ListNode(int x) : val(x), next(nullptr) {}
+ *     ListNode(int x, ListNode *next) : val(x), next(next) {}
+ * };
+ */
 class Solution {
 public:
   ListNode *reverseList(ListNode *head) {
-    // Base case: reached the end of list
+    // Recursion
-    if (!head || !(head->next)) {
+    if (head == nullptr || head->next == nullptr) {
+      // base case: return the tail
       return head;
     }
 
-    // node is the end of the initial linked list, which stays the same
+    // have to call itself before modifying, since head->next will point to
-    ListNode *node = reverseList(head->next);
+    // nullptr
+    ListNode *newHead = reverseList(head->next);
 
-    // move head after head->next
-    // notice that the node before head still points to head!
     head->next->next = head;
+    head->next = nullptr;
 
-    // since the order is reversed, head->next now points to the tail of the linked list. This is the genius part of this algorithm
+    return newHead;
-    head->next = NULL;
-
-    return node;
   }
 };
 ```