vault backup: 2022-07-09 10:15:12
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@ -61,10 +61,45 @@ Note that [[Leetcode First-Bad-Version#Constraints]], n can be 2**31, which mean
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To address that, according to [[Binary Search Algorithm#How to implement Binary search]], use `mid = l + (r - l) / 2`
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In my first iteration,
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I use a `first` variable to keep track of the first bad version.
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Later I realized that by the definition of Bi-search, left boundary will converge to the first one.
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### Solution
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Second version, 0ms
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```cpp
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// The API isBadVersion is defined for you.
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// bool isBadVersion(int version);
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class Solution {
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public:
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int firstBadVersion(int n) {
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// variant of BS
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// 1-indexed
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int r = n;
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int l = 1;
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int mid;
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do {
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mid = l + (r - l) / 2;
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if (isBadVersion(mid)) {
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// Search left
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r = mid - 1;
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} else {
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l = mid + 1;
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}
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} while (l <= r);
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return l;
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}
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};
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```
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First iteration, 4ms
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```cpp
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// The API isBadVersion is defined for you.
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// bool isBadVersion(int version);
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