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# Leetcode Binary-Tree-Inorder-Traversal
#### 2022-07-04 15:42
> ##### Algorithms:
> #algorithm #DFS #DFS_inorder
> ##### Data structures:
> #DS #binary_tree
> ##### Difficulty:
> #coding_problem #difficulty-easy
> ##### Additional tags:
> #leetcode
> ##### Revisions:
> N/A
##### Related topics:
```expander
tag:#DFS
```
- [[Leetcode Binary-Tree-Preorder-Traversal]]
##### Links:
- [Link to problem](https://leetcode.com/problems/binary-tree-inorder-traversal/)
___
### Problem
Given the `root` of a binary tree, return _the inorder traversal of its nodes' values_.
#### Examples
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg)
**Input:** root = [1,null,2,3]
**Output:** [1,3,2]
**Example 2:**
**Input:** root = []
**Output:** []
**Example 3:**
**Input:** root = [1]
**Output:** [1]
#### Constraints
- The number of nodes in the tree is in the range `[0, 100]`.
- `-100 <= Node.val <= 100`
### Thoughts
> [!summary]
> This is a #DFS traversal problem
Many of them are same to [[Leetcode Binary-Tree-Preorder-Traversal]]
### Solution
Recursion
```cpp
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left),
* right(right) {}
* };
*/
class Solution {
void inorder(TreeNode *root, vector<int> &answer) {
if (!root) {
return;
}
inorder(root->left, answer);
answer.push_back(root->val);
inorder(root->right, answer);
}
public:
vector<int> inorderTraversal(TreeNode *root) {
// Recursion.
vector<int> answer;
inorder(root, answer);
return answer;
}
};
```
Iteration
```cpp
```

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#### 2022-07-04 14:51
> ##### Algorithms:
> #algorithm #DFS #DFS_preorder
> #algorithm #DFS #DFS_preorder #Morris_traversal
> ##### Data structures:
> #DS #binary_tree
> ##### Difficulty:
> #coding_problem #difficulty-easy
> ##### Additional tags:
> #leetcode
> #leetcode #CS_list_need_understanding
> ##### Revisions:
> N/A
##### Related topics:
```expander
tag:#
tag:#DFS
```
- [[Leetcode Binary-Tree-Inorder-Traversal]]
##### Links:
@ -62,6 +63,7 @@ The recursion version is easy to implement.
Use Stacks for the iteration method, because stacks are FILO, the **subtree will get traversed first.**
And remember to push **right subtree** first, so that the left one will be traversed first.
The Morris traversal needs more understandings.
### Solution
Iteration