From 5009118bee8c439189958c72e4df834c589f21a7 Mon Sep 17 00:00:00 2001
From: juan <juancloudcomputing@protonmail.com>
Date: Mon, 4 Jul 2022 15:01:29 +0800
Subject: [PATCH] vault backup: 2022-07-04 15:01:29

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+# Leetcode Binary-Tree-Preorder-Traversal
+
+#### 2022-07-04 14:51
+
+> ##### Algorithms:
+> #algorithm #DFS #DFS_preorder
+> ##### Data structures:
+> #DS #binary_tree
+> ##### Difficulty:
+> #coding_problem #difficulty-easy
+> ##### Additional tags:
+> #leetcode
+> ##### Revisions:
+> N/A
+
+##### Related topics:
+```expander
+tag:#
+```
+ 
+ 
+
+##### Links:
+- [Link to problem](https://leetcode.com/problems/binary-tree-preorder-traversal/)
+___
+### Problem
+Given the `root` of a binary tree, return _the preorder traversal of its nodes' values_.
+
+#### Examples
+**Example 1:**
+
+![](https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg)
+
+**Input:** root = [1,null,2,3]
+**Output:** [1,2,3]
+
+**Example 2:**
+
+**Input:** root = []
+**Output:** []
+
+**Example 3:**
+
+**Input:** root = [1]
+**Output:** [1]
+#### Constraints
+-   The number of nodes in the tree is in the range `[0, 100]`.
+-   `-100 <= Node.val <= 100`
+### Thoughts
+
+> [!summary]
+> This is a #binary_tree #DFS_preorder problem. 
+
+Preorder, means root is at the "Pre" position, so the order is:
+
+- Search root node
+- Search left sub-tree
+- Search right sub-tree
+The recursion version is easy to implement.
+
+### Solution
+
+Recursion:
+```cpp
+/**
+ * Definition for a binary tree node.
+ * struct TreeNode {
+ *     int val;
+ *     TreeNode *left;
+ *     TreeNode *right;
+ *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
+ *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
+ *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left),
+ * right(right) {}
+ * };
+ */
+class Solution {
+public:
+  vector<int> preorderTraversal(TreeNode *root) {
+    // If the node is empty
+    if (root == nullptr) {
+      return {};
+    }
+    // First check root
+    vector<int> answer;
+
+    answer.push_back(root->val);
+
+    vector<int> left = preorderTraversal(root->left);
+    answer.insert(answer.end(), left.begin(), left.end());
+
+    vector<int> right = preorderTraversal(root->right);
+    answer.insert(answer.end(), right.begin(), right.end());
+
+    return answer;
+  }
+};
+
+```
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