add 4th problem
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32
pset3/4-count.c
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32
pset3/4-count.c
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#include <stdio.h>
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int main(void) {
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// Initialize counts
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int count3 = 0, count5 = 0, count7 = 0;
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int count = 0;
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// Get input
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int input;
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scanf("%d", &input);
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while (input != 0) {
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// Add up counts
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if ((input % 3 == 0) && (input % 5 != 0) && (input % 7 != 0)) {
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count3++;
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} else if ((input % 5 == 0) && (input % 7 != 0) && (input % 3 != 0)) {
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count5++;
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} else if ((input % 7 == 0) && (input % 5 != 0) && (input % 3 != 0)) {
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count7++;
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}
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count++;
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scanf("%d", &input);
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}
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// Print answers
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printf("%.2f%%\n%.2f%%\n%.2f%%\n", 100 * count3 / (float)count,
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100 * count5 / (float)count, 100 * count7 / (float)count);
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return 0;
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}
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